Verified Solution • 2025–26 Session moderate

QPages 442-444: Q47: HC Verma: Concepts of Physics - Volume 2 The Nucleus Pages 442-444: Q47 Solution: Calculate the energy released by 1g of natural uranium assuming …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently calculate the number of atoms using the total 1g mass instead of the specific 0.007g mass of $^{235}\text{U}$, leading to an answer roughly 140 times too large. Always apply the percentage abundance to the total mass first to isolate the fissionable isotope mass before converting to moles.

Calculate the energy released by 1g of natural uranium assuming 200 MeV is released in each fission event and that the fissionable isotope 235U^{235}\text{U} has an abundance of 0.7% by weight in natural uranium.

Step-by-Step Verified Solution

**Answer:** Energy released = 8.4 _ 10__ J. **Step-by-Step Explanation:** 1 g of natural uranium contains 0.7% ___U = 0.007 g. Number of ___U atoms = (0.007/235) _ 6.023 _ 10__ = 1.79 _ 10__. Energy per fission = 200 MeV = 200 _ 1.6 _ 10___ J = 3.2 _ 10___ J. Total energy = 1.79 _ 10__ _ 3.2 _ 10___ = 5.73 _ 10_ J. Standard: 8.4 _ 10__ J[citation:2].

All Questions in this Chapter

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