Verified Solution • 2025–26 Session moderate

QPages 442-444: Q4: HC Verma: Concepts of Physics - Volume 2 The Nucleus Pages 442-444: Q4 Solution: How much energy is released in the following reaction : .…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently substitute the mass of a hydrogen atom ($1.007825 \text{ u}$) for the mass of a proton ($1.007276 \text{ u}$) when the reaction is written in terms of bare nuclei. Since the problem specifies a proton ($p$) rather than a hydrogen isotope ($^1\text{H}$), you must use the specific proton mass to avoid a significant error in the calculated mass defect.

How much energy is released in the following reaction : 7Li+p→α+α^7\text{Li} + p \to \alpha + \alpha. Atomic mass of 7Li=7.0160 u^7\text{Li} = 7.0160 \text{ u} and that of 4He=4.0026 u^4\text{He} = 4.0026 \text{ u}.

Step-by-Step Verified Solution

**Answer:** Energy released = 16.83 MeV. **Step-by-Step Explanation:** Reaction: _Li + p _ _ + _. Mass of _Li = 7.0160 u, mass of p = 1.007276 u, mass of _ = 4.0026 u. Initial mass = 7.0160 + 1.007276 = 8.023276 u. Final mass = 2 _ 4.0026 = 8.0052 u. Mass defect _m = 8.023276 - 8.0052 = 0.018076 u. Energy released = 0.018076 _ 931.5 = 16.83 MeV[citation:3].

All Questions in this Chapter

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