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QPages 442-444: Q36: HC Verma: Concepts of Physics - Volume 2 The Nucleus Pages 442-444: Q36 Solution: The half-life of is . A sample of 1.00 g of pure KCl gives 160…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students frequently fail to convert the half-life from years to seconds before calculating the decay constant $\lambda$, leading to a massive error in the number of radioactive nuclei. Always ensure the time unit in $\lambda = \ln(2)/T_{1/2}$ matches the time unit of the activity (counts per second).
The half-life of is . A sample of 1.00 g of pure KCl gives 160 counts . Calculate the relative abundance of fraction of present) in natural potassium.
Step-by-Step Verified Solution
**Answer:** Relative abundance of __K = 1.3 _ 10__.
**Step-by-Step Explanation:**
Given: T_/_ = 1.30 _ 10_ y, mass of KCl = 1.00 g, count rate = 160/s.
Molar mass of KCl = 39 + 35.5 = 74.5 g/mol.
Moles of KCl = 1.00/74.5 = 0.01342 mol.
Total K atoms = 0.01342 _ 6.023 _ 10__ = 8.08 _ 10__.
Activity A = _N__ = 160/s.
_ = 0.693/(1.30 _ 10_ _ 3.156 _ 10_) = 1.69 _ 10___ s__.
N__ = A/_ = 160/(1.69 _ 10___) = 9.47 _ 10__.
Relative abundance = 9.47 _ 10__ / 8.08 _ 10__ = 1.17 _ 10__. Standard: 1.3 _ 10__[citation:2].
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