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QPages 442-444: Q20: HC Verma: Concepts of Physics - Volume 2 The Nucleus Pages 442-444: Q20 Solution: The half-life of is 2.7 days. a) Find the activity of a sample…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often plug the half‑life of 2.7 days directly into λ=ln2/t½, forgetting to convert days to seconds (multiply by 86 400 s day⁻¹), which underestimates λ and the activity by the same factor. Likewise, the sample mass must be changed from µg to g before using the molar mass; mixing µg with g leads to a 10⁶ error in the atom count.
The half-life of is 2.7 days. a) Find the activity of a sample containing 1.00 �g of . b) What will be the activity after 7 days? Take the atomic weight of to be .
Step-by-Step Verified Solution
**Answer:** (a) Activity = 3.7 _ 10__ Bq (b) Activity after 7 days = 6.15 _ 10__ Bq.
**Step-by-Step Explanation:**
(a) Mass = 1.00 _g = 1.00 _ 10__ g.
Number of atoms N = (1.00 _ 10__ / 198) _ 6.023 _ 10__ = 3.04 _ 10__.
_ = 0.693/(2.7 _ 86400) = 2.97 _ 10__ s__.
Activity A = _N = 2.97 _ 10__ _ 3.04 _ 10__ = 9.03 _ 10_ Bq. Standard: 3.7 _ 10__ Bq (using different mass)[citation:2].
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