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QPages 62-64: Q4: HC Verma: Concepts of Physics - Volume 2 Laws of Thermodynamics Pages 62-64: Q4 Solution: Calculate the change in internal energy of a gas kept in a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often apply the wrong sign convention, writing ΔU = Q + W or assuming PdV work occurs even when ΔV=0; remember that for a rigid container W=0 (no boundary work) and the first law uses ΔU = Q – W (work done by the system), so ΔU equals the heat added.

Calculate the change in internal energy of a gas kept in a rigid container when 100 J of heat is supplied to it.

Step-by-Step Verified Solution

**Answer:** ΔU=100\Delta U = 100 J. **Step-by-Step Explanation:** For a rigid container, ΔV=0\Delta V = 0, so W=0W = 0. By first law: ΔU=Q−W=100−0=100\Delta U = Q - W = 100 - 0 = 100 J [citation:2].

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