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QPage 60: Q3: HC Verma: Concepts of Physics - Volume 2 Laws of Thermodynamics Page 60: Q3 Solution: A cylinder containing a gas is lifted from the first floor to…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often think that lifting the cylinder does work on the gas, but the gas only does work on the piston as it expands. The external agent lifts the piston, not the gas itself, so the work done on the gas is zero. Remember that the work done on the gas is $W_{ ext{on}}=-P_{ ext{ext}}Delta V$, which vanishes when the external pressure remains effectively constant during the lift.

A cylinder containing a gas is lifted from the first floor to the second floor. What is the amount of work done on the gas? What is the amount of work done by the gas? Is the internal energy of the gas increased? Is the temperature of the gas increased?

Step-by-Step Verified Solution

**Answer:** Work done on the gas = 0. Work done by the gas = PΔVP\Delta V (positive). Internal energy and temperature changes depend on the nature of the walls. **Step-by-Step Explanation:** When the cylinder is lifted, atmospheric pressure decreases slightly, so the gas expands. Work done **on** the gas is zero; work is done **by** the gas. Work done by the gas W=PΔVW = P\Delta V (positive, since ΔV>0\Delta V > 0). Whether internal energy and temperature increase depends on whether the cylinder walls are **conducting** (heat exchange possible) or **insulating** (adiabatic). Without knowing this, we cannot determine the change in UU or TT [citation:8][citation:10].

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