Verified Solution • 2025–26 Session moderate

QPage 61: Q8: HC Verma: Concepts of Physics - Volume 2 Laws of Thermodynamics Page 61: Q8 Solution: Consider two processes on a system as shown in figure. The…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often treat $W=\int PdV$ as a state function and assume equal initial and final volumes give equal work; remember that work is path‑dependent, so the larger enclosed area (process B) yields $\Delta W_2>\Delta W_1$.

Consider two processes on a system as shown in figure. The volumes in the initial states are the same in the two processes and the volumes in the final states are also the same. Let

\Delta W_1

and

\Delta W_2

be the work done by the system in the processes A and B respectively.

Multiple Choice Options

A $\Delta W_1 > \Delta W_2$
B $\Delta W_1 = \Delta W_2$
C $\Delta W_1 < \Delta W_2$
D Nothing can be said about the relation between $\Delta W_1$ and $\Delta W_2$

Step-by-Step Verified Solution

**Answer:** (c) _W_ < _W_. **Step-by-Step Explanation:** From the figure, process B has a larger area under the curve than process A. So _W_ < _W_.

All Questions in this Chapter

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