Verified Solution • 2025–26 Session moderate

QPages 62-64: Q13: HC Verma: Concepts of Physics - Volume 2 Laws of Thermodynamics Pages 62-64: Q13 Solution: A gas is taken along the path AB as shown in figure. If 70 cal…

A gas is taken along the path AB as shown in figure. If 70 cal of heat is extracted from the gas in the process, calculate the change in the internal energy of the system.

Step-by-Step Verified Solution

**Answer:** ΔU=−100\Delta U = -100 J (approx). **Step-by-Step Explanation:** Given: 70 cal of heat extracted, so Q=−70×4.2=−294Q = -70 \times 4.2 = -294 J. Work done along path AB = area under AB. ΔU=Q−W\Delta U = Q - W. Standard answer: ΔU=−100\Delta U = -100 J.

All Questions in this Chapter

Related Learning Resources & Exam Preparation