QJEEAdv17Maf0bc
Physics - Class 11
• Chapter 1: Mathematical tools for Physics
Let O be the origin and let PQR be an arbitrary triangle. The point S is such that $\overrightarrow{OP}$ . $\overrightarrow{OQ}$ + $\overrightarrow{OR}$ . $\overrightarrow{OS}$ = $\overrightarrow{OR}$ . $\overrightarrow{OP}$ + $\overrightarrow{OQ}$ . $\overrightarrow{OS}$ = $\overrightarrow{OQ}$ . $\overrightarrow{OR}$ + $\overrightarrow{OP}$ . $\overrightarrow{OS}$ Then the triangle PQR has S as its
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QJEEAdv17Mac807
Physics - Class 11
• Chapter 1: Mathematical tools for Physics
| O X → × O Y → | = ?
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QJEEAdv17Ph05b2
Physics - Class 11
• Chapter 8: System of Particles and Rotational Motion
A wheel of radius R and mass M is placed at the bottom of a fixed step of height R as shown in the figure. A constant force is continuously applied on the surface of the wheel so that it just climbs the step without slipping. Consider the torque τ about an axis normal to the plane of the paper passing through the point Q. Which of the following options is/are correct?
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QJEEAdv17Pha62e
Physics - Class 11
• Chapter 8: System of Particles and Rotational Motion
Consider regular polygons with number of sides $n=3,4,5....$ as shown in the figure. The center of mass of all the polygons is at height $h$ from the ground. They roll on a horizontal surface about the leading vertex without slipping and sliding as depicted. The maximum increase in height of the locus of the center of mass for each polygon is $\Delta$ . Then $\Delta$ depends on $n$ and $h$ as
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QJEEAdv17Phfc09
Physics - Class 11
• Chapter 8: System of Particles and Rotational Motion
The total kinetic energy of the ring is
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QJEEAdv17Ch8075
Chemistry - Class 11
• Unit 5: Thermodynamics
The standard state Gibbs free energies of formation of $C$ (graphite) and $C$ (diamond) at $T=298$ $K$ are ${\Delta _f}{G^0}$ [ $C$ (graphite)] $= 0kJmo{l^{ - 1}}$ ${\Delta _f}{G^0}$ [ $C$ (diamond)] $= 2.9kJmo{l^{ - 1}}$ The standard state means that the pressure should be $1$ bar, and substance should be pure at a given temperature. The conversion of graphite [ $C$ (graphite)] to diamond [ $C$ (diamond)] reduces its volume by $2 \times {10^{ - 6}}\,{m^3}\,mo{l^{ - 1}}$ If $C$ (graphite) is converted to $C$ (diamond) isothermally at $T=298$ $K,$ the pressure at which $C$ (graphite) is in equilibrium with $C$ (diamond), is [Useful information : $1$ $J=1$ $kg\,{m^2}{s^{ - 2}};1\,Pa = 1\,kg\,{m^{ - 1}}{s^{ - 2}};$ $1$ bar $= {10^5}$ $Pa$ ]
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QJEEAdv17Chfb75
Chemistry - Class 11
• Unit 5: Thermodynamics
For a reaction taking place in a container in equilibrium with its surroundings, the effect of temperature on its equilibrium constant K in terms of change in entropy is described by
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QJEEAdv17Ch5c10
Chemistry - Class 11
• Unit 7 – Redox Reactions
The order of the oxidation state of the phosphorous atom in ${H_3}P{O_2},{H_3}P{O_4},{H_3}P{O_3}$ and ${H_4}{P_2}{O_6}$ is
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QJEEAdv17Che281
Chemistry - Class 11
• Unit 8: Organic Chemistry – Some Basic Principles and Techniques
For the following compounds, the correct statement(s) with respect to nucleophilic substitution reaction is (are)
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QJEEAdv17Ma2ca5
Mathematics - Class 11
• Chapter 5: Complex Numbers & Quadratic Equations
If a 4 = 28, then p + 2q =
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QJEEAdv17Madc8b
Mathematics - Class 11
• Chapter 5: Complex Numbers & Quadratic Equations
a 12 = ?
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QJEEAdv17Mafc3f
Mathematics - Class 11
• Chapter 2: Relations and Functions
Let S = {1, 2, 3, .........., 9}. For k = 1, 2, .........., 5, let N k be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N 1 + N 2 + N 3 + N 4 + N 5 =
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QJEEAdv17Ma9fcd
Mathematics - Class 11
• Chapter 3: Trigonometric Functions
Let $\alpha$ and $\beta$ be non zero real numbers such that $2(\cos \beta - \cos \alpha ) + \cos \alpha \cos \beta = 1$ . Then which of the following is/are true?
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QJEEAdv17Ph1887
Physics - Class 12
• Chapter–10: Wave Optics
Two coherent monochromatic point sources ${S_1}$ and ${S_2}$ of wavelength $\lambda = 600\,nm$ are placed symmetrically on either side of the center of the circle as shown. The sources are separated by a distance $d=1.8$ $mm.$ This arrangement produces interference fringes visible as alternate bright and dark spots on the circumference of the circle. The angular separation between two consecutive bright spots is $\Delta \theta .$ Which of the following options is/are correct?
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QJEEAdv17Ph69b3
Physics - Class 12
• Chapter–5: Magnetism and Matter
A symmetric star shaped conducting wire loop is carrying a steady state current I as shown in the figure. The distance between the diametrically opposite vertices of the star is 4 a . The magnitude of the magnetic field at the center of the loop is
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QJEEAdv17Ph4f49
Physics - Class 12
• Chapter–7: Alternating Current
The instantaneous voltages at three terminals marked $X,Y$ and $Z$ are given by ${V_x} = {V_0}\,\sin \,\omega t,$ ${V_Y} = {V_0}\,\sin$ $\left( {\omega t + {{2\pi } \over 3}} \right)$ and $Vz = {V_0}\sin \left( {\omega t + {{4\pi } \over 3}} \right)$ An ideal voltmeter is configured to read $rms$ value of the potential difference between its terminals. It is connected between points $X$ and $Y$ and then between $Y$ and $Z.$ The reading(s) of the voltmeter will be
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QJEEAdv17Ph7909
Physics - Class 12
• Chapter–8: Electromagnetic Waves
A source of constant voltage V is connected to a resistance R and two ideal inductors L 1 and L 2 through a switch S as shown. There is no mutual inductance between the two inductors. The switch S is initially open. At t = 0, the switch is closed and current begins to flow. Which of the following options is/are correct?
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QJEEAdv17Phafbf
Physics - Class 12
• Chapter–2: Electrostatic Potential and Capacitance
In Process 2, total energy dissipated across the resistance E D is
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QJEEAdv17Mac741
Mathematics - Class 12
• Chapter 11: Differential Equations
If y = y(x) satisfies the differential equation ${8\sqrt x \left( {\sqrt {9 + \sqrt x } } \right)dy = {{\left( {\sqrt {4 + \sqrt {9 + \sqrt x } } } \right)}^{ - 1}}}$ dx, x > 0 and y(0) = $\sqrt 7$ , then y(256) =
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QJEEAdv17Ma300e
Mathematics - Class 12
• Chapter 13: Probability
Three randomly chosen nonnegative integers x, y and z are found to satisfy the equation x + y + z = 10. Then the probability that z is even, is
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QJEEAdv17Ma6c81
Mathematics - Class 12
• Chapter 7: Continuity & Differentiability
If f : R → R is a twice differentiable function such that f"(x) > 0 for all x ∈ R, and f ( 1 2 ) = 1 2 , f(1) = 1, then
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QJEEAdv17Ma0365
Mathematics - Class 12
• Chapter 7: Continuity & Differentiability
Let $f(x) = {{1 - x(1 + |1 - x|)} \over {|1 - x|}}\cos \left( {{1 \over {1 - x}}} \right)$ for x $\ne$ 1. Then
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QJEEAdv17Mae8d4
Mathematics - Class 12
• Chapter 10: Applications of Integrals
If the line x = $\alpha$ divides the area of region R = {(x, y) $\in$ R 2 : x 3 $\le$ y $\le$ x, 0 $\le$ x $\le$ 1} into two equal parts, then
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QJEEAdv17Cha29c
Chemistry - Class 12
• Chapter 13: Amines
The major product of the following reaction is
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QJEEAdv17Chcad0
Chemistry - Class 12
• Chapter 13: Amines
The order of basicity among the following compounds is
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QJEEAdv17Ch40a6
Chemistry - Class 12
• Chapter 5: Surface Chemistry
The correct statement(s) about surface properties is (are)
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QJEEAdv17Ch7b53
Chemistry - Class 12
• Chapter 8 : d and f Block Elements
The options(s) with only amphoteric oxides is (are)
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QJEEAdv17Che565
Chemistry - Class 12
• Chapter 2: Solutions
Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water as 2 kg m o l − 1 . The figures shown below represent plots of vapor pressure ( V . P . ) versus temperature ( T ) . [molecular weight of ethanol is 46 g m o l − 1 . ] Among the following, the option representing change in the freezing point is
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