QJEEAdv17Ch5c10: JEE Advanced 2017 Chemistry - Class 11 JEEAdv17Ch5c10 Solution: The order of the oxidation state of the phosphorous atom in and …

Question

Verified Solution • 2025–26 Session moderate

The order of the oxidation state of the phosphorous atom in

{H_3}P{O_2},{H_3}P{O_4},{H_3}P{O_3}

and

{H_4}{P_2}{O_6}

is

Accepted Answer

Let oxidation states of phosphorus in H₃PO₂, H₃PO₄, H₃PO₃ and H₄P₂O₆ be p, q, r and s respectively.

Oxidation state of hydrogen = + 1

Oxidation state of oxygen = $-$ 2

Thus, in H₃PO₂ :

3 $\times$ (+1) + p + 2 $\times$ ( $-$ 2) = 0 $\therefore$ p = +1

In H₃PO₄ :

3 $\times$ (+1) + q + 4 $\times$ ( $-$ 2) = 0 $\therefore$ q = +5

In H₃PO₃ :

3 $\times$ (+1) + r + 3 $\times$ ( $-$ 2) = 0 $\therefore$ r = + 3

In H₄P₂O₆ :

4 $\times$ (+1) + 2s + 6 $\times$ ( $-$ 2) = 0 $\therefore$ s = +4

Thus, the order of oxidation state is :

H₃PO₄ > H₄P₂O₆ > H₃PO₃ > H₃PO₂

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