Verified Solution • 2025–26 Session moderate

QJEEAdv17Mafc3f: JEE Advanced 2017 Mathematics - Class 11 JEEAdv17Mafc3f Solution: Let S = {1, 2, 3, .........., 9}. For k = 1, 2, .........., 5,…

Let S = {1, 2, 3, .........., 9}. For k = 1, 2, .........., 5, let Nk be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N1 + N2 + N3 + N4 + N5 =

Multiple Choice Options

  • A 210
  • B 252
  • C 126
  • D 125

Step-by-Step Verified Solution

Ni=5Ck×4C5−k

N1=5×1N2=10×4N3=10×6N4=5×4N5=1N1+N2+N3+N4+N5=126

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