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QJEEAdv17Mac807: JEE Advanced 2017 Physics - Class 11 JEEAdv17Mac807 Solution:

|OX→ × OY→| = ?

Multiple Choice Options

  • A sin(P + Q)
  • B sin(P + R)
  • C sin(Q + R)
  • D sin2R

Step-by-Step Verified Solution

JEE Advanced 2017 Paper 2 Offline Mathematics - Vector Algebra Question 10 English Explanation

Now, OX→=QR→QR

and OY→=RP→RP

Therefore, (OX→×OY→)=QR→QR×RP→RP=QR→×RP→PQ

=PQsin⁡RPQ=sin⁡R=sin⁡(π−(P+Q)=sin⁡(P+Q))

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