Verified Solution • 2025–26 Session moderate

QJEEAdv17Ph3d50: JEE Advanced 2017 Physics - Class 12 JEEAdv17Ph3d50 Solution: In Process 1, the energy stored in the capacitor E C and heat…

In Process 1, the energy stored in the capacitor EC and heat dissipated across resistance ED are related by

Multiple Choice Options

  • A EC = ED ln2
  • B EC = ED
  • C EC = 2ED
  • D EC = 12{1 \over 2} ED

Step-by-Step Verified Solution

Energy supplied to the circuit is CV 02_0^2

Energy stored in capacitor, EC = 12{1\over 2} CV 02_0^2

Therefore,

Energy dissipated E0 = Energy supplied −- Energy stored

= CV 02_0^2 −- 12{1\over 2} CV 02_0^2 = 12{1\over 2} CV 02_0^2

⇒\Rightarrow EC = ED

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