QJEEAdv17Ma10be: JEE Advanced 2017 Mathematics - Class 12 JEEAdv17Ma10be Solution: If g ( x ) = ∫ sin ⁡ x sin ⁡ ( 2 x ) sin − 1 ( t ) d t , then

Question

Verified Solution • 2025–26 Session moderate

If

g (x) = \int_{\sin x}^{\sin (2 x)} \sin^{- 1} (t) d t

, then

Accepted Answer

g (x) = \int_{\sin x}^{\sin (2 x)} \sin^{- 1} (t) d t

g'(x) = 2cos 2x sin^{$-$ 1}(sin2 x)

-

cos x sin^{$-$ 1}(sin x)

g^{'} (\frac{π}{2}) = - 2 \sin^{- 1} (0) = 0

g^{'} (- \frac{π}{2}) = - 2 \sin^{- 1} (0) = 0

No option is matching.

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