JEE Advanced 2008 Question Paper with Solutions

Verified PYQs • Step-by-Step Solutions

Browse official JEE Advanced 2008 previous year question papers with detailed step-by-step verified explanations, official answer keys, and chapter-wise categorization on PrepChimp.

JEE Advanced 2008 Questions & Solutions

QJEEAdv08Ph5e10 Physics - Class 11 • Chapter 9: Gravitation

A spherically symmetric gravitational system of particles has a mass density ρ = { ρ 0 f o r r ≤ R 0 f o r r > R Where ρ 0 is a constant. A test mass can undergo circular motion under the influence of the gravitational field of particles. Its speed V as a function of distance r ( 0 < r < ∞ ) from the centre of the system is represented by

View Step-by-Step Verified Solution →
QJEEAdv08Phd26b Physics - Class 11 • Chapter 8: System of Particles and Rotational Motion

STATEMENT - 1 : Two cylinders, one hollow (metal) and the other solid (wood) with the same mass and identical dimensions are simultaneously allowed to roll without slipping down an inclined plane from the same height. The hollow cylinder will reach the bottom of the inclined plane first. and STATEMENT - 2 : By the principle of conservation of energy, the total kinetic energies of both the cylinders are identical when they reach the bottom of the incline.

View Step-by-Step Verified Solution →
QJEEAdv08Phee4a Physics - Class 11 • Chapter 12: Thermal Properties of matter

STATEMENT - 1 : The stream of water flowing at high speed from a garden hose pipe tends to spread line a fountain when held vertically up, but tends to narrow down when held vertically down. and STATEMENT - 2 : In any steady flow of an incompressible fluid, the volume flow rate of the fluid remains constant.

View Step-by-Step Verified Solution →
QJEEAdv08Phcd50 Physics - Class 11 • Chapter 6: Laws of motion

If collision between the block and the incline is completely elastic, then the vertical (upward) component of the velocity of the block at point B, immediately after it strikes the second incline is

View Step-by-Step Verified Solution →
QJEEAdv08Ch095e Chemistry - Class 11 • Unit 8: Organic Chemistry – Some Basic Principles and Techniques

Hyperconjugation involves overlapping of the following orbitals:

View Step-by-Step Verified Solution →
QJEEAdv08Ch2510 Chemistry - Class 11 • Unit 2: Structure of Atom

STATEMENT - 1 : The plot of atomic number (y-axis) versus number of neutrons (x-axis) for stable nuclei shows a curvature towards x-axis from the line of 45 o slope as the atomic number is increased. STATEMENT - 2 : Proton-proton electrostatic repulsions begin to overcome attractive forces involving protons and neutrons in heavier nuclides

View Step-by-Step Verified Solution →
QJEEAdv08Chcd61 Chemistry - Class 11 • Unit 8: Organic Chemistry – Some Basic Principles and Techniques

The correct statement(s) concerning the structures E, F and G is(are) :

View Step-by-Step Verified Solution →
QJEEAdv08Ma8ae2 Mathematics - Class 11 • Chapter 9: Sequences & Series

Let ${S_n} = \sum\limits_{k = 1}^n {{n \over {{n^2} + kn + {k^2}}}}$ and ${T_n} = \sum\limits_{k = 0}^{n - 1} {{n \over {{n^2} + kn + {k^2}}}}$ for $n$ $=1, 2, 3, ............$ Then,

View Step-by-Step Verified Solution →
QJEEAdv08Ma66df Mathematics - Class 11 • Chapter 11: Conic Sections

Let $P\left( {{x_1},{y_1}} \right)$ and $Q\left( {{x_2},{y_2}} \right),{y_1} < 0,{y_2} < 0,$ be the end points of the latus rectum of the ellipse ${x^2} + 4{y^2} = 4.$ The equations of parabolas with latus rectum $PQ$ are :

View Step-by-Step Verified Solution →
QJEEAdv08Mad5e0 Mathematics - Class 11 • Chapter 5: Complex Numbers & Quadratic Equations

Let z be any point in A ∩ B ∩ C Then, | z + 1 − i | 2 + | z − 5 − i | 2 lies between :

View Step-by-Step Verified Solution →
QJEEAdv08Mafd54 Mathematics - Class 11 • Chapter 5: Complex Numbers & Quadratic Equations

Let z be any point A ∩ B ∩ C and let w be any point satisfying | w − 2 − i | < 3 . Then, | z | − | w | + 3 lies between :

View Step-by-Step Verified Solution →
QJEEAdv08Ph800a Physics - Class 12 • Chapter–10: Wave Optics

In a Young's double slit experiment, the separation between the two slits is d and the wavelength of the light is λ . The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2. Choose the correct choice(s).

View Step-by-Step Verified Solution →
QJEEAdv08Phc751 Physics - Class 12 • Chapter–5: Magnetism and Matter

A particle of mass m and charge q, moving with velocity v enters Region II normal to the boundary as shown in the figure. Region II has a uniform magnetic field B perpendicular to the plane of the paper. The length of the Region II is l . Choose the correct choice (s).

View Step-by-Step Verified Solution →
QJEEAdv08Ph80f6 Physics - Class 12 • Chapter–3: Current Electricity

STATEMENT - 1 In a Meter Bridge experiment, null point for an unknown resistance is measured. Now, the unknown resistance is put inside an enclosure maintained at a higher temperature. The null point can be obtained at the same point as before by decreasing the value of the standard resistance. and STATEMENT - 2 Resistance of a metal increases with increase in temperature.

View Step-by-Step Verified Solution →
QJEEAdv08Ph4ff1 Physics - Class 12 • Chapter–9: Ray Optics and Optical Instruments

Two beams of red and violet colours are made to pass separately through a prism (angle of the prism is 60 $^\circ$ ). In the position of minimum deviation, the angle of refraction will be :

View Step-by-Step Verified Solution →
QJEEAdv08Ma4227 Mathematics - Class 12 • Chapter 7: Continuity & Differentiability

Let $g(x) = {{{{(x - 1)}^n}} \over {\log {{\cos }^m}(x - 1)}};0 < x < 2,m$ and $n$ are integers, $m \ne 0,n > 0$ , and let $p$ be the left hand derivative of $|x - 1|$ at $x = 1$ . If $\mathop {\lim }\limits_{x \to {1^ + }} g(x) = p$ , then

View Step-by-Step Verified Solution →
QJEEAdv08Ma81c2 Mathematics - Class 12 • Chapter 4: Determinants

Consider the system of equations: x − 2 y + 3 z = − 1 − x + y − 2 z = k x − 3 y + 4 z = 1 Statement - 1 : The system of equations has no solution for k ≠ 3 . and Statement - 2 : The determinant | 1 3 − 1 − 1 − 2 k 1 4 1 | ≠ 0 , for k ≠ 3 .

View Step-by-Step Verified Solution →
QJEEAdv08Ma297e Mathematics - Class 12 • Chapter 11: Differential Equations

Let f and g be real valued functions defined on interval ( − 1 , 1 ) such that g ″ ( x ) is continuous, g ( 0 ) ≠ 0. g ′ ( 0 ) = 0 , g ″ ( 0 ) ≠ 0 , and f ( x ) = g ( x ) sin ⁡ x STATEMENT - 1: lim x → 0 [ g ( x ) cot ⁡ x − g ( 0 ) cos ⁡ e c x ] = f ″ ( 0 ) and STATEMENT - 2: f ′ ( 0 ) = g ( 0 )

View Step-by-Step Verified Solution →
QJEEAdv08Ma402e Mathematics - Class 12 • Chapter 10: Applications of Integrals

The area of the region bounded by the curve $y=f(x),$ the $x$ -axis, and the lines $x=a$ and $x=b$ , where $- \infty < a < b < - 2,$ is :

View Step-by-Step Verified Solution →
QJEEAdv08Ma8e4d Mathematics - Class 12 • Chapter 11: Differential Equations

If $f\left( { - 10\sqrt 2 } \right) = 2\sqrt 2 ,$ then $f''\left( { - 10\sqrt 2 } \right) =$

View Step-by-Step Verified Solution →
QJEEAdv08Ch0c19 Chemistry - Class 12 • Chapter 2: Solutions

Water is added to the solution M such that the fraction of water in the solution becomes 0.9 mole. The boiling point of this solution is:

View Step-by-Step Verified Solution →
QJEEAdv08Ch6dd8 Chemistry - Class 12 • Chapter 6: General Principles and Processes of Isolation of Elements

Native silver metal forms a water soluble complex with a dilute aqueous solution of NaCN in the presence of:

View Step-by-Step Verified Solution →