QJEEAdv08Ph5e10
Physics - Class 11
• Chapter 9: Gravitation
A spherically symmetric gravitational system of particles has a mass density ρ = { ρ 0 f o r r ≤ R 0 f o r r > R Where ρ 0 is a constant. A test mass can undergo circular motion under the influence of the gravitational field of particles. Its speed V as a function of distance r ( 0 < r < ∞ ) from the centre of the system is represented by
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QJEEAdv08Phd26b
Physics - Class 11
• Chapter 8: System of Particles and Rotational Motion
STATEMENT - 1 : Two cylinders, one hollow (metal) and the other solid (wood) with the same mass and identical dimensions are simultaneously allowed to roll without slipping down an inclined plane from the same height. The hollow cylinder will reach the bottom of the inclined plane first. and STATEMENT - 2 : By the principle of conservation of energy, the total kinetic energies of both the cylinders are identical when they reach the bottom of the incline.
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QJEEAdv08Phee4a
Physics - Class 11
• Chapter 12: Thermal Properties of matter
STATEMENT - 1 : The stream of water flowing at high speed from a garden hose pipe tends to spread line a fountain when held vertically up, but tends to narrow down when held vertically down. and STATEMENT - 2 : In any steady flow of an incompressible fluid, the volume flow rate of the fluid remains constant.
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QJEEAdv08Phcc13
Physics - Class 11
• Chapter 6: Laws of motion
The speed of the block at point C, immediately before it leaves the second incline is
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QJEEAdv08Phcd50
Physics - Class 11
• Chapter 6: Laws of motion
If collision between the block and the incline is completely elastic, then the vertical (upward) component of the velocity of the block at point B, immediately after it strikes the second incline is
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QJEEAdv08Chc68a
Chemistry - Class 11
• Unit 10: The s-Block Elements
Aqueous solutions of Na 2 S 2 O 3 on reaction with Cl 2 gives:
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QJEEAdv08Ch9ad9
Chemistry - Class 11
• Unit 13: States of Matter: Gases and Liquids
A gas described by van Der Waals equation
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QJEEAdv08Ch095e
Chemistry - Class 11
• Unit 8: Organic Chemistry – Some Basic Principles and Techniques
Hyperconjugation involves overlapping of the following orbitals:
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QJEEAdv08Ch2510
Chemistry - Class 11
• Unit 2: Structure of Atom
STATEMENT - 1 : The plot of atomic number (y-axis) versus number of neutrons (x-axis) for stable nuclei shows a curvature towards x-axis from the line of 45 o slope as the atomic number is increased. STATEMENT - 2 : Proton-proton electrostatic repulsions begin to overcome attractive forces involving protons and neutrons in heavier nuclides
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QJEEAdv08Chcd61
Chemistry - Class 11
• Unit 8: Organic Chemistry – Some Basic Principles and Techniques
The correct statement(s) concerning the structures E, F and G is(are) :
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QJEEAdv08Ma8ae2
Mathematics - Class 11
• Chapter 9: Sequences & Series
Let ${S_n} = \sum\limits_{k = 1}^n {{n \over {{n^2} + kn + {k^2}}}}$ and ${T_n} = \sum\limits_{k = 0}^{n - 1} {{n \over {{n^2} + kn + {k^2}}}}$ for $n$ $=1, 2, 3, ............$ Then,
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QJEEAdv08Ma66df
Mathematics - Class 11
• Chapter 11: Conic Sections
Let $P\left( {{x_1},{y_1}} \right)$ and $Q\left( {{x_2},{y_2}} \right),{y_1} < 0,{y_2} < 0,$ be the end points of the latus rectum of the ellipse ${x^2} + 4{y^2} = 4.$ The equations of parabolas with latus rectum $PQ$ are :
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QJEEAdv08Ma52c9
Mathematics - Class 11
• Chapter 11: Conic Sections
Points E and F are given by
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QJEEAdv08Mad5e0
Mathematics - Class 11
• Chapter 5: Complex Numbers & Quadratic Equations
Let z be any point in A ∩ B ∩ C Then, | z + 1 − i | 2 + | z − 5 − i | 2 lies between :
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QJEEAdv08Mafd54
Mathematics - Class 11
• Chapter 5: Complex Numbers & Quadratic Equations
Let z be any point A ∩ B ∩ C and let w be any point satisfying | w − 2 − i | < 3 . Then, | z | − | w | + 3 lies between :
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QJEEAdv08Ph800a
Physics - Class 12
• Chapter–10: Wave Optics
In a Young's double slit experiment, the separation between the two slits is d and the wavelength of the light is λ . The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2. Choose the correct choice(s).
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QJEEAdv08Phc751
Physics - Class 12
• Chapter–5: Magnetism and Matter
A particle of mass m and charge q, moving with velocity v enters Region II normal to the boundary as shown in the figure. Region II has a uniform magnetic field B perpendicular to the plane of the paper. The length of the Region II is l . Choose the correct choice (s).
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QJEEAdv08Ph80f6
Physics - Class 12
• Chapter–3: Current Electricity
STATEMENT - 1 In a Meter Bridge experiment, null point for an unknown resistance is measured. Now, the unknown resistance is put inside an enclosure maintained at a higher temperature. The null point can be obtained at the same point as before by decreasing the value of the standard resistance. and STATEMENT - 2 Resistance of a metal increases with increase in temperature.
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QJEEAdv08Ph9dd1
Physics - Class 12
• Chapter–12: Atoms
The wavelength of light emitted in the visible region by He + ions after collisions with H atoms is
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QJEEAdv08Ph4ff1
Physics - Class 12
• Chapter–9: Ray Optics and Optical Instruments
Two beams of red and violet colours are made to pass separately through a prism (angle of the prism is 60 $^\circ$ ). In the position of minimum deviation, the angle of refraction will be :
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QJEEAdv08Ma4227
Mathematics - Class 12
• Chapter 7: Continuity & Differentiability
Let $g(x) = {{{{(x - 1)}^n}} \over {\log {{\cos }^m}(x - 1)}};0 < x < 2,m$ and $n$ are integers, $m \ne 0,n > 0$ , and let $p$ be the left hand derivative of $|x - 1|$ at $x = 1$ . If $\mathop {\lim }\limits_{x \to {1^ + }} g(x) = p$ , then
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QJEEAdv08Ma81c2
Mathematics - Class 12
• Chapter 4: Determinants
Consider the system of equations: x − 2 y + 3 z = − 1 − x + y − 2 z = k x − 3 y + 4 z = 1 Statement - 1 : The system of equations has no solution for k ≠ 3 . and Statement - 2 : The determinant | 1 3 − 1 − 1 − 2 k 1 4 1 | ≠ 0 , for k ≠ 3 .
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QJEEAdv08Ma297e
Mathematics - Class 12
• Chapter 11: Differential Equations
Let f and g be real valued functions defined on interval ( − 1 , 1 ) such that g ″ ( x ) is continuous, g ( 0 ) ≠ 0. g ′ ( 0 ) = 0 , g ″ ( 0 ) ≠ 0 , and f ( x ) = g ( x ) sin x STATEMENT - 1: lim x → 0 [ g ( x ) cot x − g ( 0 ) cos e c x ] = f ″ ( 0 ) and STATEMENT - 2: f ′ ( 0 ) = g ( 0 )
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QJEEAdv08Ma402e
Mathematics - Class 12
• Chapter 10: Applications of Integrals
The area of the region bounded by the curve $y=f(x),$ the $x$ -axis, and the lines $x=a$ and $x=b$ , where $- \infty < a < b < - 2,$ is :
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QJEEAdv08Ma8e4d
Mathematics - Class 12
• Chapter 11: Differential Equations
If $f\left( { - 10\sqrt 2 } \right) = 2\sqrt 2 ,$ then $f''\left( { - 10\sqrt 2 } \right) =$
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QJEEAdv08Chfb9f
Chemistry - Class 12
• Chapter 7: The p-Block Elements
Among the following, the correct statement is :
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QJEEAdv08Ch0c19
Chemistry - Class 12
• Chapter 2: Solutions
Water is added to the solution M such that the fraction of water in the solution becomes 0.9 mole. The boiling point of this solution is:
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QJEEAdv08Ch6dd8
Chemistry - Class 12
• Chapter 6: General Principles and Processes of Isolation of Elements
Native silver metal forms a water soluble complex with a dilute aqueous solution of NaCN in the presence of:
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QJEEAdv08Ch8bf9
Chemistry - Class 12
• Chapter 2: Solutions
The freezing point of the solution M is :
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QJEEAdv08Chdbd1
Chemistry - Class 12
• Chapter 7: The p-Block Elements
Among the following, the correct statement is:
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