Verified Solution • 2025–26 Session moderate

QJEEAdv08Chbadc: JEE Advanced 2008 Chemistry - Class 12 JEEAdv08Chbadc Solution: The structure of compounds J and K, respectively, are:

The structure of compounds J and K, respectively, are:

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/dddb23c4f07e7bb85db79d1efe6eac13c4c73accf404329fa21e415dba23a6c4.webp
  • B https://ik.imagekit.io/novatra/photos/2ad7983d27db3a215a01383dc13b518ffbf610a0d08afb93b1359fb53e027447.webp
  • C https://ik.imagekit.io/novatra/photos/f7407d686a60ec9c9902f33935498104b980ee67fb18b73aaf84bdfbd937905a.webp
  • D https://ik.imagekit.io/novatra/photos/ca22af70d5ff3ec0dfece3df37c1cee44c088fbb4dd2b92f26b5c02a2bf5edb4.webp

Step-by-Step Verified Solution

IIT-JEE 2008 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 16 English Explanation

The alkyl bromide reacts with Mg to form alkyl magnesium bromide (Grignard reagent) which attacks carbon dioxide followed by hydrolysis to form a carboxylic acid (compound J).

It reacts with thionyl chloride (compound K) to form acid chloride.

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