QJEEAdv08Mad5e0: JEE Advanced 2008 Mathematics - Class 11 JEEAdv08Mad5e0 Solution: Let z be any point in A ∩ B ∩ C Then,

Question

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Let z be any point in $A \cap B \cap C$

Then, ${| z + 1 - i |}^{2} + {| z - 5 - i |}^{2}$ lies between :

Accepted Answer

$| z + 1 - i |^{2} + | z - 5 - i |^{2}$

The points ( $- 1, 1$ ) and (5, 1) are the extremities of the diameter of the given circle of radius 3

Hence, PA $^{2}$ + PB $^{2}$ = AB $^{2}$ = 36

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