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QJEEAdv08Ma3200: JEE Advanced 2008 Mathematics - Class 12 JEEAdv08Ma3200 Solution: Let Which of the following is true?

Let g(x)=∫0exf′(t)1+t2 dt.g\left( x \right) = \int\limits_0^{{e^x}} {{{f'\left( t \right)} \over {1 + {t^2}}}} \,dt.

Which of the following is true?

Multiple Choice Options

  • A g′(x)g'(x) is positive on (−∞,0)\left( { - \infty ,0} \right) and negative on (0,∞)\left( {0,\infty } \right)
  • B g′(x)g'(x) is negative on (−∞,0)\left( { - \infty ,0} \right) and positive on (0,∞)\left( {0,\infty } \right)
  • C g′(x)g'(x) changes sign on both (−∞,0)\left( { - \infty ,0} \right) and (0,∞)\left( {0,\infty } \right)
  • D g′(x)g'(x) does not change sign on (−∞,0)\left( { - \infty ,0} \right)

Step-by-Step Verified Solution

Given g′(x)=∫0exf′(t)dt1+t2g'(x) = \int\limits_0^{{e^x}} {{{f'(t)dt} \over {1 + {t^2}}}}

g′′(x)=dg(x)d(ex). d(ex)dxg''(x) = {{dg(x)} \over {d({e^x})}}.\,{{d({e^x})} \over {dx}}

=f′(ex)1+e2x . ex= {{f'({e^x})} \over {1 + {e^{2x}}}}\,.\,{e^x}

= {{{e^x}} \over {1 + {e^{2x}}}}\,.\,{{2a({e^{2x}} - 1)} \over {{{({e^{2x}} + a{e^x} + 1)}^2}}} > 0

when x∈(0,∞)x \in (0,\infty )

g′(x)g'(x) < 0 when x∈(−∞,0)x \in ( - \infty ,0)

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