QJEEAdv17Chb93d: JEE Advanced 2017 Chemistry - Class 12 JEEAdv17Chb93d Solution: and are, respectively

Question

Verified Solution • 2025–26 Session moderate

Y

and

Z

are, respectively

Accepted Answer

Reaction of

\mathrm{P}_4 \mathrm{O}_{10}

with pure nitric acid

\left(\mathrm{HNO}_3\right)

gives dinitrogen pentaoxide

\left(\mathrm{N}_2 \mathrm{O}_5\right)

and metaphosphoric acid

\left(\mathrm{HPO}_3\right)

\mathrm{P}_4 \mathrm{O}_{10}+4 \mathrm{HNO}_3 \rightarrow \underset{Z}{4 \mathrm{HPO}_3}+\underset{Y}{2 \mathrm{~N}_2 \mathrm{O}_5}

The compound

\mathrm{Y}

is dinitrogen pentaoxide

\left(\mathrm{N}_2 \mathrm{O}_5\right)

and compound

\mathrm{Z}

is metaphosphoric

\operatorname{acid}\left(\mathrm{HPO}_3\right)

.

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