HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q7 Solution: Suppose the energy liberated in the recombination of a…

QPages 419-421: Q7: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q7 Solution: Suppose the energy liberated in the recombination of a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently misread “maximum wavelength” as the shortest wavelength and thus assign a larger photon energy; remember that $E=hc/\lambda$ so the longest emitted wavelength gives the smallest photon energy, which equals the band‑gap energy in this ideal recombination.

Suppose the energy liberated in the recombination of a hole-electron pair is converted into electromagnetic radiation. If the maximum wavelength emitted is 820 nm, what is the band gap? Use Planck constant

h = 4.14 \times 10^{-15} \text{ eV-s}

, Boltzmann constant

k = 8.62 \times 10^{-5} \text{ eV/K}

Step-by-Step Verified Solution

**Answer:** Band gap = 1.5 eV. **Step-by-Step Explanation:** Given: Maximum wavelength = 820 nm.

E = \frac{1240}{820} = 1.51 \text{ eV} \approx 1.5 \text{ eV}

QPages 419-421: Q7: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q7 Solution: Suppose the energy liberated in the recombination of a…

Step-by-Step Verified Solution

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