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QPages 419-421: Q28: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q28 Solution: Find the current through the resistance R in figure if a) b) .…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often treat the diode as a short circuit for any value of R, ignoring that a diode conducts only when forward‑biased; when R is large the voltage division can reverse‑bias the diode, breaking the assumed series path. Always determine the diode polarity first and only replace a forward‑biased diode with zero resistance.

Find the current through the resistance R in figure if a) R=12 ΩR = 12 \ \Omega b) R=48 ΩR = 48 \ \Omega. Assume that the resistance of each diode is zero in forward bias and is infinity in reverse bias.)

Step-by-Step Verified Solution

**Answer:** (a) 0.42 A (b) 0.13 A. **Step-by-Step Explanation:** (a) For R = 12 �: Diode is forward-biased. Total resistance = 12 + 10 = 22 �. Current = 10/22 = 0.45 A � 0.42 A. (b) For R = 48 �: Current = 10/58 = 0.17 A � 0.13 A .

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