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QPages 419-421: Q2: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q2 Solution: In a pure semiconductor, the number of conduction electron per…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often multiply the carrier concentration ($6\times10^{19}\,$m$^{-3}$) by a volume expressed in cm$^3$ or mm$^3$ without converting to m$^3$, producing an exponent error. Always convert every linear dimension to metres first, compute the volume in m$^3$, then multiply by the concentration to obtain the correct number of carriers.

In a pure semiconductor, the number of conduction electron 6×10196 \times 10^{19} per cubic metre. How many holes are there in a sample of size 1 cm _ 1 mm?

Step-by-Step Verified Solution

**Answer:** Number of holes = 6 _ 10__. **Step-by-Step Explanation:** In a pure semiconductor, the number of conduction electrons equals the number of holes. Given: conduction electron concentration n = 6 _ 10__ per m_. Volume = 1 cm _ 1 cm _ 1 mm = 1 cm _ 1 cm _ 0.1 cm = 0.1 cm_ = 10__ m_. Number of electrons in this volume = 6 _ 10__ _ 10__ = 6 _ 10__. Hence, number of holes = 6 _ 10__ .

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