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QPages 417-418: Q12: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 417-418: Q12 Solution: Two identical capacitors A and B are charged to the same…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often ignore the diode’s one‑way nature and apply the $Q=Q_0e^{-t/RC}$ decay to both capacitors; remember that a forward‑biased diode blocks reverse current, so the capacitor in that branch retains its initial charge $Q=CV$ while only the resistor‑only branch follows the exponential decay.

Two identical capacitors A and B are charged to the same potential V and are connected in two circuits at t = 0 as shown in figure. The charges on the capacitors at a time t = CR are, respectively,

Multiple Choice Options

  • A VC, VC
  • B VC/e, VC
  • C VC, VC/e
  • D VC/e, VC/e.

Step-by-Step Verified Solution

**Answer:** (c) VC, VC/e. **Step-by-Step Explanation:** Capacitor A is in a circuit with a diode that blocks discharge, so it retains charge VC. Capacitor B discharges through the resistor, so its charge is VC/e after time CR.

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