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QPages 419-421: Q19: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q19 Solution: When a p-n junction is reverse-biased, the current becomes…
When a p-n junction is reverse-biased, the current becomes almost constant at 25 �A. When it is forward-biased at 200 mV, a current of 75 �A is obtained. Find the magnitude of diffusion current when the diode is a) unbiased, b) reverse-biased at 200 mV and c) forward-biased at 200 mV.
Step-by-Step Verified Solution
**Answer:** (a) 25 _A (b) 25 _A (c) 100 _A.
**Step-by-Step Explanation:**
Given: Reverse saturation current = 25 _A. Forward current at 200 mV = 75 _A.
(a) Unbiased: net current = 0, but diffusion current = drift current = 25 _A.
(b) Reverse-biased at 200 mV: current = 25 _A.
(c) Forward-biased at 200 mV: current = 75 _A. Standard: 100 _A .
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