Verified Solution • 2025–26 Session moderate

QPages 419-421: Q31: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q31 Solution: When the base current in a transistor is changed from 30 �A to…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often subtract currents and forget to keep the same unit prefixes, treating 80 µA − 30 µA as 50 A and 3.5 mA − 1.0 mA as 2500 A, which inflates the numbers. Convert all currents to the same unit (e.g., µA or mA) before forming the ratio $\beta = \Delta I_C/\Delta I_B$.

When the base current in a transistor is changed from 30 �A to 80 �A, the collector current is changed from 1.0 mA to 3.5 mA. Find the current gain β\beta.

Step-by-Step Verified Solution

**Answer:** _ = 50. **Step-by-Step Explanation:** Given: _I_B = 80 - 30 = 50 _A, _I_C = 3.5 - 1.0 = 2.5 mA = 2500 _A.
β=ΔICΔIB=250050=50\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{2500}{50} = 50

All Questions in this Chapter

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