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QPages 419-421: Q25: HC Verma: Concepts of Physics - Volume 2 Semiconductors and Semiconductor Devices Pages 419-421: Q25 Solution: Find the currents through the resistance in the circuits shown…
⚠️ Common Exam Traps & Conceptual Pitfalls
When a diode is forward‑biased, replace it with a short circuit and redraw the circuit. The resistors that were originally in series may become parallel, and vice‑versa. Failing to do this can lead to an incorrect current calculation, such as treating two 10 Ω resistors as 20 Ω instead of 5 Ω in parallel.
Find the currents through the resistance in the circuits shown in figure. Assume that the resistance of each diode is zero in forward bias and is infinity in reverse bias.)
Step-by-Step Verified Solution
**Answer:** (a) 1 A (b) Zero.
**Step-by-Step Explanation:**
(a) When V_A > V_B, the diodes conduct. The circuit simplifies to two 10 � resistors in parallel = 5 �. Current = 5/5 = 1 A.
(b) When V_A < V_B, the diodes are reverse-biased. No current flows .
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