HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q6 Solution: The pressures of the gas in a constant volume gas thermometer…

QPages 12-14: Q6: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q6 Solution: The pressures of the gas in a constant volume gas thermometer…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly assume the temperature is proportional to the absolute pressure ($T \propto P$) or fail to subtract the ice point pressure from the steam point pressure in the denominator. You must use the linear interpolation formula $T = 100 \times \frac{P - P_{ice}}{P_{steam} - P_{ice}}$, ensuring the numerator and denominator both represent the change in pressure relative to the ice point, not the raw pressure values.

The pressures of the gas in a constant volume gas thermometer are 80 cm, 90 cm and 100 cm of mercury at the ice point, the steam point and in a heated wax bath, respectively. Find the temperature of the wax bath.

Step-by-Step Verified Solution

**Answer:**

T = 100�\text{C}

**Step-by-Step Explanation:** At ice point (0�C):

P = 80

cm. At steam point (100�C):

P = 90

cm. At wax bath:

P = 100

cm.

T = 100 \times \frac{100 - 80}{90 - 80} = 100 \times \frac{20}{10} = 200�\text{C}

Standard answer:

200�\text{C}

QPages 12-14: Q6: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q6 Solution: The pressures of the gas in a constant volume gas thermometer…

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