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QPages 12-14: Q5: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q5 Solution: The pressure of the gas in a constant volume gas thermometer is …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often plug the ice (0 °C) and steam (100 °C) temperatures directly into $P\propto T$ and obtain a wrong pressure. Always convert to absolute temperature (K) by adding 273.15 before forming the ratio $P_2=P_1\frac{T_2}{T_1}$.

The pressure of the gas in a constant volume gas thermometer is 70 kPa at the ice point. Find the pressure at the steam point.

Step-by-Step Verified Solution

**Answer:** P=95.6 kPaP = 95.6 \text{ kPa} **Step-by-Step Explanation:** Ice point: T1=273.15T_1 = 273.15 K, P1=70P_1 = 70 kPa. Steam point: T2=373.15T_2 = 373.15 K.
P2=P1×T2T1=70×373.15273.15=95.6 kPaP_2 = P_1 \times \frac{T_2}{T_1} = 70 \times \frac{373.15}{273.15} = 95.6 \text{ kPa}

All Questions in this Chapter

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