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QPages 12-14: Q15: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q15 Solution: A metre scale is made up of steel and measures correct length…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often confuse the direction of error, assuming a scale that expands reads larger values; in reality, an expanded scale has larger divisions, causing it to read a value smaller than the true length (negative error). Always determine if the scale expands or contracts relative to the calibration temperature to correctly assign the sign of the percentage error.

A metre scale is made up of steel and measures correct length at 16�C. What will be the percentage error if this scale is used a) on a summer day when the temperature is 46�C and b) on a winter day when the temperature is 6�C? Coefficient of linear expansion of steel = 11×10−6 �C−111 \times 10^{-6} \text{ �C}^{-1}.

Step-by-Step Verified Solution

**Answer:** (a) Error on summer day: 0.033%0.033\% (b) Error on winter day: 0.011%0.011\% **Step-by-Step Explanation:** Calibrated at 16�C. (a) At 46�C: ΔT=30�C\Delta T = 30�\text{C}. Scale expands by αΔT=11×10−6×30=3.3×10−4\alpha \Delta T = 11 \times 10^{-6} \times 30 = 3.3 \times 10^{-4}. Error = 0.033%0.033\%. (b) At 6�C: ΔT=−10�C\Delta T = -10�\text{C}. Scale contracts by 11×10−5=1.1×10−411 \times 10^{-5} = 1.1 \times 10^{-4}. Error = 0.011%0.011\%.

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