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QPages 11-12: Q8: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 11-12: Q8 Solution: If the temperature of a uniform rod is slightly increased by ,…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often forget that the moment of inertia depends on the square of the length ($L^2$), leading them to incorrectly assume a linear increase of $alpha I Delta t$. You must apply the binomial approximation to $(1+alpha Delta t)^2$ to correctly identify the factor of 2 in the change.
If the temperature of a uniform rod is slightly increased by , its moment of inertia about a perpendicular bisector increases by
Multiple Choice Options
- A zero
- B
- C
- D
Step-by-Step Verified Solution
**Answer:** (c) 2_I_t.
**Step-by-Step Explanation:**
For a uniform rod, the moment of inertia about a perpendicular bisector is I = ML_/12. When temperature increases by _t, L increases by _L = L__t. The new moment of inertia I' = M(L+_L)_/12 � I(1 + 2__t). Hence, the increase is 2_I_t.
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