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QPages 12-14: Q13: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q13 Solution: A circular hole of diameter 2.00 cm is made in an aluminium…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently assume a heated hole contracts, forgetting that thermal expansion is uniform; the hole’s diameter grows by the same fractional amount as the plate, so apply the linear expansion formula $d = d_0(1+\alpha\Delta T)$ directly to the diameter, not to the area or radius.

A circular hole of diameter 2.00 cm is made in an aluminium plate at 0�C. What will be the diameter at 100�C? α\alpha for aluminium = 2.3×10−5 �C−12.3 \times 10^{-5} \text{ �C}^{-1}.

Step-by-Step Verified Solution

**Answer:** d=2.0046 cmd = 2.0046 \text{ cm} **Step-by-Step Explanation:** d0=2.00d_0 = 2.00 cm, ΔT=100�C\Delta T = 100�\text{C}, α=2.3×10−5\alpha = 2.3 \times 10^{-5} /�C.
d=d0(1+αΔT)=2(1+2.3×10−5×100)=2(1.0023)=2.0046 cmd = d_0(1 + \alpha \Delta T) = 2(1 + 2.3 \times 10^{-5} \times 100) = 2(1.0023) = 2.0046 \text{ cm}

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