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QPages 12-14: Q2: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q2 Solution: A constant-volume thermometer registers a pressure of at the…

⚠️ Common Exam Traps & Conceptual Pitfalls

When using a constant‑volume gas thermometer, the pressure is proportional to the absolute temperature, so you must insert temperatures in kelvins (not °C) and use absolute pressures; mixing Celsius values or gauge pressures gives a wrong boiling‑point temperature.

A constant-volume thermometer registers a pressure of

1.500 \times 10^4 \text{ Pa}

at the triple point of water and a pressure of

2.050 \times 10^4 \text{ Pa}

at the normal boiling point. What is the temperature at the normal boiling point?

Step-by-Step Verified Solution

**Answer:**

T = 373.25 \text{ K}

**Step-by-Step Explanation:** Triple point of water:

T_{tp} = 273.16

K,

P_{tp} = 1.500 \times 10^4

Pa. At normal boiling point,

P = 2.050 \times 10^4

Pa. Using

T = T_{tp} \times P/P_{tp}

:

T = 273.16 \times \frac{2.050 \times 10^4}{1.500 \times 10^4} = 273.16 \times 1.3667 = 373.25 \text{ K}

All Questions in this Chapter

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