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QPages 12-14: Q22: HC Verma: Concepts of Physics - Volume 2 Heat and Temperature Pages 12-14: Q22 Solution: The volume of a glass vessel is 1000 cc at 20�C. What volume of …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often set $V_{glass}\beta_{glass}=V_{Hg}\beta_{Hg}$ using the full 1000 cc vessel volume, forgetting that the glass expansion acts on the *remaining air volume* $(V_{glass}-V_{Hg})$, not on the whole container. Use $ (V_{glass}-V_{Hg})\beta_{glass}=V_{Hg}\beta_{Hg}$ to avoid the error.

The volume of a glass vessel is 1000 cc at 20�C. What volume of mercury should be poured into it at this temperature so that the volume of the remaining space does not change with temperature? Coefficients of cubical expansion of mercury and glass are 1.8×10−4 �C−11.8 \times 10^{-4} \text{ �C}^{-1} and 9.0×10−6 �C−19.0 \times 10^{-6} \text{ �C}^{-1}, respectively.

Step-by-Step Verified Solution

**Answer:** VHg=68.5 ccV_{Hg} = 68.5 \text{ cc} **Step-by-Step Explanation:** For the remaining space to be constant: ΔVHg=ΔVglass\Delta V_{Hg} = \Delta V_{glass}. VHgγHg=VglassγglassV_{Hg}\gamma_{Hg} = V_{glass}\gamma_{glass} VHg×1.8×10−4=1000×9.0×10−6V_{Hg} \times 1.8 \times 10^{-4} = 1000 \times 9.0 \times 10^{-6} VHg=1000×9.0×10−61.8×10−4=50 ccV_{Hg} = \frac{1000 \times 9.0 \times 10^{-6}}{1.8 \times 10^{-4}} = 50 \text{ cc}

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