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QPages 330-331: Q6: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 330-331: Q6 Solution: The dielectric strength of air is . A parallel-plate…

The dielectric strength of air is 3.0×106 V/m3.0 \times 10^6 \text{ V/m}. A parallel-plate air-capacitor has area 20 cm220 \text{ cm}^2 and plate separation 0.10 mm. Find the maximum rms voltage of an AC source that can be safely connected to this capacitor.

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**Answer:** Vrms≈212 VV_{rms} \approx 212 \, \text{V}. **Step-by-Step Explanation:** Maximum voltage V0=E×d=3×106×0.1×10−3=300 VV_0 = E \times d = 3 \times 10^6 \times 0.1 \times 10^{-3} = 300 \, \text{V}. Vrms=V02≈212 VV_{rms} = \frac{V_0}{\sqrt{2}} \approx 212 \, \text{V} [citation:6].

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