Verified Solution • 2025–26 Session moderate

QPages 330-331: Q17: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 330-331: Q17 Solution: An inductor-coil, a capacitor and an AC source of rms voltage…

An inductor-coil, a capacitor and an AC source of rms voltage 24 V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0 A is observed. If this inductor coil is connected to a battery of emf 12 V and internal resistance 4.0 Ω4.0 \ \Omega, what will be the current?

Step-by-Step Verified Solution

**Answer:** Current =1.5 A= 1.5 \, \text{A}. **Step-by-Step Explanation:** At resonance, impedance is purely resistive. Irms=6 AI_{rms} = 6 \, \text{A}, Vrms=24 VV_{rms} = 24 \, \text{V}, so R=4 ΩR = 4 \, \Omega. When connected to 12 V battery with internal resistance 4 Ω4 \, \Omega, total resistance =8 Ω= 8 \, \Omega. Current =128=1.5 A= \frac{12}{8} = 1.5 \, \text{A} [citation:4].

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