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QPages 328-329: Q4: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 328-329: Q4 Solution: Can the peak voltage across the inductor be greater than the…

Can the peak voltage across the inductor be greater than the peak voltage of the source in an LCR circuit?

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**Answer:** Yes. **Step-by-Step Explanation:** In an LCR circuit at resonance, the current is i=VRi = \frac{V}{R}. The voltage across the inductor is VL=iXL=VRXLV_L = i X_L = \frac{V}{R} X_L. If XLR>1\frac{X_L}{R} > 1 (which is possible for a high-Q circuit), then VL>VV_L > V. The peak voltage across the inductor can exceed the source peak voltage [citation:1][citation:16].

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