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QPages 328-329: Q5: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 328-329: Q5 Solution: In a circuit, containing a capacitor and an AC source, the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often assume $V=IR$ holds for every element, but for a capacitor the current is $i=C, rac{dV}{dt}$. At a voltage peak $dV/dt=0$, so $i=0$, which is perfectly consistent with the capacitor’s constitutive relation and does not contradict Ohm’s law for resistive elements.

In a circuit, containing a capacitor and an AC source, the current is zero at the instant the source voltage is maximum. Is it consistent with Ohm's Law?

Step-by-Step Verified Solution

**Answer:** Yes, it is consistent. **Step-by-Step Explanation:** Ohm's law (V=IRV = IR) is valid only for purely resistive circuits. For a capacitor, the current is i=CdVdti = C \frac{dV}{dt}. When the source voltage is maximum, its rate of change is zero, so the current is zero. This behaviour is perfectly consistent with the capacitor's constitutive relation, not Ohm's law [citation:1][citation:16].

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