Verified Solution • 2025–26 Session moderate

QPages 328-329: Q2: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 328-329: Q2 Solution: The voltage and current in a series AC circuit are given by and …

The voltage and current in a series AC circuit are given by V=V0cos⁡ωtV = V_0 \cos \omega t and i=i0sin⁡ωti = i_0 \sin \omega t. What is the power dissipated in the circuit?

Step-by-Step Verified Solution

**Answer:** Zero. **Step-by-Step Explanation:** The voltage is V=V0cos⁡ωtV = V_0 \cos \omega t and current is i=i0sin⁡ωt=i0cos⁡(ωt−π/2)i = i_0 \sin \omega t = i_0 \cos(\omega t - \pi/2). The phase difference between voltage and current is ϕ=π/2\phi = \pi/2. The average power is P=VrmsIrmscos⁡ϕ=VrmsIrmscos⁡(π/2)=0P = V_{rms} I_{rms} \cos\phi = V_{rms} I_{rms} \cos(\pi/2) = 0 [citation:14][citation:16].

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