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QPages 330-331: Q3: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 330-331: Q3 Solution: A bulb rated 60 W at 220 V is connected across a household…

A bulb rated 60 W at 220 V is connected across a household supply of alternating voltage of 220 V. Calculate the maximum instantaneous current through the filament.

Step-by-Step Verified Solution

**Answer:** Imax≈0.39 AI_{max} \approx 0.39 \, \text{A}. **Step-by-Step Explanation:** R=V2P=220260=806.67 ΩR = \frac{V^2}{P} = \frac{220^2}{60} = 806.67 \, \Omega. Imax=V0R=311.08806.67≈0.39 AI_{max} = \frac{V_0}{R} = \frac{311.08}{806.67} \approx 0.39 \, \text{A} [citation:6].

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