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QPages 330-331: Q18: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 330-331: Q18 Solution: Following figure shows a typical circuit for a low-pass filter. …
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often plug the frequency $f$ directly into the low‑pass formula $V_0=V_i/\sqrt{1+(\omega RC)^2}$, forgetting that $\omega=2\pi f$. This missing factor of $2\pi$ (or using the wrong component values) leads to an output voltage off by roughly an order of magnitude. Always convert $f$ to angular frequency before evaluating $\omega RC$.
Following figure shows a typical circuit for a low-pass filter. An AC input is applied at the left end and the output is received at the right end. Find the output voltage for , and . Note that as the frequency is increased the output decreases and, hence, the name low-pass filter.
Step-by-Step Verified Solution
**Answer:** (a) (b) (c) .
**Step-by-Step Explanation:**
This is a low-pass RC filter. . Given , . For , , , calculate accordingly [citation:4].
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