Verified Solution • 2025–26 Session moderate

QPages 330-331: Q5: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 330-331: Q5 Solution: The peak power consumed by a resistive coil, when connected to…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often multiply the given peak (maximum) power by the time interval, forgetting that the average power for a sinusoidal resistive load is only half the peak value ($P_{avg}=P_{peak}/2$). Always convert the peak power to its average (or RMS) value before computing energy over many cycles.

The peak power consumed by a resistive coil, when connected to an AC source, is 80 W. Find the energy consumed by the coil in 100 seconds, which is many times larger than the time period of the source.

Step-by-Step Verified Solution

**Answer:** 4000 J4000 \, \text{J}. **Step-by-Step Explanation:** The average power is Prms=P02=40 WP_{rms} = \frac{P_0}{2} = 40 \, \text{W}. Energy =Prms×t=40×100=4000 J= P_{rms} \times t = 40 \times 100 = 4000 \, \text{J} [citation:6].

All Questions in this Chapter

Related Learning Resources & Exam Preparation