Verified Solution • 2025–26 Session moderate

QPages 329-330: Q7: HC Verma: Concepts of Physics - Volume 2 Alternating Current Pages 329-330: Q7 Solution: An AC source rated 100 V rms) supplies a current of 10 A rms)…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently compute average power as $P=V_{\rm rms}I_{\rm rms}$ assuming a unity power factor, overlooking the $cos\phi$ term; remember that real power is $P=V_{\rm rms}I_{\rm rms}\cos\phi$, so it can never exceed the apparent power $V_{\rm rms}I_{\rm rms}$ and may be lower depending on the phase angle.

An AC source rated 100 V rms) supplies a current of 10 A rms) to a circuit. The average power delivered by the source

Multiple Choice Options

  • A must be 1000 W
  • B may be 1000 W
  • C may be greater than 1000 W
  • D may be less than 1000 W

Step-by-Step Verified Solution

**Answer:** (b), (d). **Step-by-Step Explanation:** Average power P = V_rms I_rms cos_. If cos_ = 1, P = 1000 W. If cos_ < 1, P < 1000 W. So it may be 1000 W or less.

All Questions in this Chapter

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