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QPages 395-396: Q22: HC Verma: Concepts of Physics - Volume 2 X-Rays Pages 395-396: Q22 Solution: The electric current in an X-ray tube from the target to the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often multiply 40 kV by 10 mA directly, forgetting to convert kV→V and mA→A; this yields a power off by a factor of $10^6$. Always express voltage in volts and current in amperes before applying $P=VI$.

The electric current in an X-ray tube from the target to the filament) operating at 40 kV is 10 mA. Assume that on an average, 1% of the total kinetic energy of the electron hitting the target are converted into X-rays. a) What is the total power emitted as X-rays and b) how much heat is produced in the target every second?

Step-by-Step Verified Solution

**Answer:** (a) Total power emitted as X-rays = 4.0 W. (b) Heat produced per second = 396 W. **Step-by-Step Explanation:** Given: V=40V = 40 kV, i=10i = 10 mA, efficiency = 1%. (a) Total power input: P=Vi=40×103×10×10−3=400P = Vi = 40 \times 10^3 \times 10 \times 10^{-3} = 400 W. Power emitted as X-rays = 0.01×400=4.00.01 \times 400 = 4.0 W. (b) Heat produced per second = 400−4=396400 - 4 = 396 W.

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