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QPages 394-395: Q5: HC Verma: Concepts of Physics - Volume 2 X-Rays Pages 394-395: Q5 Solution: The potential difference applied to an X-ray tube is increased. …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often reverse the V–λ relationship, assuming a higher accelerating voltage produces longer X‑ray wavelengths. Remember the cutoff wavelength is given by $\lambda_{\min}=\frac{hc}{eV}$, so increasing the potential difference makes $\lambda_{\min}$ smaller (shorter), not larger.

The potential difference applied to an X-ray tube is increased. As a result, in the emitted radiation,

Multiple Choice Options

  • A the intensity increases
  • B the minimum wavelength increases
  • C the intensity remains unchanged
  • D the minimum wavelength decreases.

Step-by-Step Verified Solution

**Answer:** (d) the minimum wavelength decreases. **Step-by-Step Explanation:** Increasing the potential difference decreases the cutoff wavelength.

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