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QPages 395-396: Q1: HC Verma: Concepts of Physics - Volume 2 X-Rays Pages 395-396: Q1 Solution: Find the energy, the frequency and the momentum of an X-ray…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often insert the wavelength as 0.10×10⁻⁹ m (treating 0.10 nm as 0.10 nm = 0.10×10⁻⁹ m) instead of the correct 1.0×10⁻¹⁰ m, and then use $h$ in eV·s together with $c$ in m/s without converting the resulting energy to joules before computing $p=E/c$. Keep all quantities in consistent SI units: convert the wavelength to metres, compute $E=hc/\lambda$ in joules (or keep $E$ in eV and use $p=h/\lambda$), and only then express the final answer in the desired units.

Find the energy, the frequency and the momentum of an X-ray photon of wavelength 0.10 nm. Use Planck constant h=4.14×10−15 eVsh = 4.14 \times 10^{-15} \text{ eVs}, speed of light c=3×108 m/sc = 3 \times 10^8 \text{ m/s}.)

Step-by-Step Verified Solution

**Answer:** Energy = 12.4 keV, Frequency = 3 _ 10__ Hz, Momentum = 6.61 _ 10___ kg-m/s. **Step-by-Step Explanation:** Given: _ = 0.10 nm = 0.10 _ 10__ m. Energy: E = hc/_ = (4.14 _ 10___ eV-s _ 3 _ 10_ m/s) / (0.10 _ 10__ m) = 124 _ 10_ eV = 12.4 keV [citation:8]. Frequency: _ = c/_ = (3 _ 10_) / (0.10 _ 10__) = 3 _ 10__ Hz [citation:8]. Momentum: p = E/c = (12.4 _ 10_ eV _ 1.6 _ 10___ C) / (3 _ 10_ m/s) = 6.61 _ 10___ kg-m/s [citation:8].

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