Verified Solution • 2025–26 Session moderate

QPages 394-395: Q4: HC Verma: Concepts of Physics - Volume 2 X-Rays Pages 394-395: Q4 Solution: For a given material, the energy and wavelength of…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often assume that higher‑energy X‑rays have longer wavelengths, mixing up the relationship $E=hc/\lambda$. Remember that as energy increases, wavelength decreases, so the correct order is $E(K_\alpha)<E(K_\beta)<E(K_\gamma)$ and $\lambda(K_\alpha)>\lambda(K_\beta)>\lambda(K_\gamma)$.

For a given material, the energy and wavelength of characteristic X-rays satisfy

Multiple Choice Options

A $E(K_\alpha) < E(K_\beta) < E(K_\gamma)$
B $\lambda(K_\alpha) > \lambda(K_\beta) > \lambda(K_\gamma)$
C $E(K_\alpha) < E(K_\beta) < E(K_\gamma)$
D $\lambda(K_\alpha) > \lambda(K_\beta) > \lambda(K_\gamma)$

Step-by-Step Verified Solution

**Answer:** (a), (b). **Step-by-Step Explanation:** E(K__) < E(K__) < E(K__) (a) and _(K__) > _(K__) > _(K__) (b).

All Questions in this Chapter

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