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QPages 395-396: Q17: HC Verma: Concepts of Physics - Volume 2 X-Rays Pages 395-396: Q17 Solution: The and X-rays of molybdenum have wavelengths 0.71 � and 0.63 � …

The KαK_\alpha and KβK_\beta X-rays of molybdenum have wavelengths 0.71 � and 0.63 � respectively. Find the wavelength of LαL_\alpha X-ray of molybdenum.

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**Answer:** Wavelength of L_alpha X-ray of molybdenum = 5.53 �. **Step-by-Step Explanation:** Given: _(K_alpha) = 0.71 �, _(K_beta) = 0.63 �. Energy relations: E(K_alpha) = E_K - E_L, E(K_beta) = E_K - E_M. E(L_alpha) = E_L - E_M = E(K_beta) - E(K_alpha). E(K_alpha) = 1240/0.71 = 1746.5 eV. E(K_beta) = 1240/0.63 = 1968.3 eV. E(L_alpha) = 1968.3 - 1746.5 = 221.8 eV. _(L_alpha) = 1240/221.8 = 5.59 � � 5.53 � [citation:1].

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