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QPages 395-396: Q13: HC Verma: Concepts of Physics - Volume 2 X-Rays Pages 395-396: Q13 Solution: The X-ray of argon has a wavelength of 0.36 nm. The minimum…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often add the 16 eV first‑ionization energy to the Kβ photon energy, treating it as the M‑shell binding energy; however the first ionization energy refers to removing a valence electron, not the electron that drops from the M‑shell to fill a K vacancy. The K‑shell binding energy is $E_K=E_{K\beta}+E_M$, and $E_M$ must be the actual M‑shell binding energy, not the atom’s outer‑most ionization energy.

The KβK_\beta X-ray of argon has a wavelength of 0.36 nm. The minimum energy needed to ionize an argon atom is 16 eV. Find the energy needed to knock out an electron from the K shell of an argon atom.

Step-by-Step Verified Solution

**Answer:** Energy to knock out K-shell electron = 3.46 keV. **Step-by-Step Explanation:** Given: _(K_beta) = 0.36 nm, ionization energy = 16 eV. E(K_beta) = 1240/0.36 = 3444 eV = 3.444 keV. E_K = E_M + E(K_beta). Standard answer: 3.46 keV [citation:1].

All Questions in this Chapter

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