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QPages 249-253: Q48: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 249-253: Q48 Solution: A long, cylindrical tube of inner and outer radii and carries a …
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often assume that the current flowing in the tube’s wall contributes to the Ampèrian loop inside the hollow region, leading them to calculate a non‑zero $B$ for $r<a$. Remember that an Amperian circle drawn entirely inside the cavity encloses no current, so $B=0$ there. Likewise, for the field just outside the tube the loop radius must be $r=b$, the outer surface, not the inner radius $a$, giving $B=\mu_0 i/(2\pi b)$.
A long, cylindrical tube of inner and outer radii and carries a current distributed uniformly over its cross section. Find the magnitude of the magnetic field at a point a) just inside the tube b) just outside the tube.
Step-by-Step Verified Solution
**Answer:** (a) Just inside: 0 (b) Just outside: .
**Step-by-Step Explanation:**
(a) Inside the hollow part of the tube, .
(b) Just outside the tube at radius : .
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