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QPages 249-253: Q2: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Due to a Current Pages 249-253: Q2 Solution: A current of 10 A is established in a long wire along the…

A current of 10 A is established in a long wire along the positive z-axis. Find the magnetic field B⃗\vec{B} at the point 1 m, 0, 0).

Step-by-Step Verified Solution

**Answer:** B⃗=2×10−6j^ T\vec{B} = 2 \times 10^{-6} \hat{j} \text{ T}. **Step-by-Step Explanation:** i=10i = 10 A, d=1d = 1 m. B=μ0i2πd=4π×10−7×102π×1=2×10−6B = \frac{\mu_0 i}{2\pi d} = \frac{4\pi \times 10^{-7} \times 10}{2\pi \times 1} = 2 \times 10^{-6} T. Direction: Using the right-hand rule (current along +z), the field at (1,0,0) is along +y.

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